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Top 10 Must-Know Algorithms for Beginners: Hands-On Guide to Mastering the Basics

Top 10 Algorithms for Beginners: Binary Search, Bubble Sort, Merge Sort, and More

If you’re new to coding, you might find yourself amidst a labyrinth of algorithms, trying to figure out where to begin. Fret not! We’ve gathered the top 10 algorithms that every beginner should know. From sorting techniques like Bubble Sort to more complex graph algorithms like Dijkstra’s, this post will help you kickstart your coding journey.

Top 10 Must-Know Algorithms for Beginners: Hands-On Guide to Mastering the Basics

1. Binary Search: The Detective in Action

Ever wanted to feel like Sherlock Holmes, uncovering hidden clues? Binary Search is your go-to algorithm when it comes to finding an element in a sorted array. This method divides the array into halves, progressively narrowing down the search.

def binary_search(arr, x):
    low = 0
    high = len(arr) - 1
    mid = 0
  
    while low <= high:
        mid = (high + low) // 2
        if arr[mid] < x:
            low = mid + 1
        elif arr[mid] > x:
            high = mid - 1
        else:
            return mid
    return -1
  
arr = [2, 3, 4, 10, 40]
x = 10
result = binary_search(arr, x)
print("Element is at index", str(result))

If Sherlock was a programmer, this is one of the algorithms he’d use! ?️‍♂️

2. Bubble Sort: Bubbles Rise to the Top

As simple as it sounds, Bubble Sort compares each pair of adjacent elements and swaps them if they’re in the wrong order. Laughably inefficient for large datasets but makes sorting feel like a breeze for beginners.

def bubble_sort(arr):
    n = len(arr)
    for i in range(n):
        for j in range(0, n-i-1):
            if arr[j] > arr[j+1]:
                arr[j], arr[j+1] = arr[j+1], arr[j]
    return arr
  
arr = [64, 34, 25, 12, 22, 11, 90]
sorted_arr = bubble_sort(arr)
print("Sorted array is:", sorted_arr)

A joke to lighten the mood: Why did the Bubble Sort algorithm go to therapy? Because it had too many swap issues! ?

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3. Merge Sort: Divide and Conquer

Merge Sort works by dividing the unsorted list into n sublists, each containing one element, and then merging those sublists to produce a sorted list.

def merge_sort(arr):
    if len(arr) > 1:
        mid = len(arr)//2
        L = arr[:mid]
        R = arr[mid:]

        merge_sort(L)
        merge_sort(R)

        i = j = k = 0

        while i < len(L) and j < len(R):
            if L[i] < R[j]:
                arr[k] = L[i]
                i += 1
            else:
                arr[k] = R[j]
                j += 1
            k += 1

        while i < len(L):
            arr[k] = L[i]
            i += 1
            k += 1

        while j < len(R):
            arr[k] = R[j]
            j += 1
            k += 1
    return arr
  
arr = [12, 11, 13, 5, 6, 7]
sorted_arr = merge_sort(arr)
print("Sorted array is:", sorted_arr)

4. QuickSort: The Swift Sort

QuickSort employs a divide and conquer strategy. It picks an element as the pivot and partitions the array around the picked pivot.

def partition(arr, low, high):
    i = (low-1)
    pivot = arr[high]
  
    for j in range(low, high):
        if arr[j] <= pivot:
            i = i+1
            arr[i], arr[j] = arr[j], arr[i]
  
    arr[i+1], arr[high] = arr[high], arr[i+1]
    return (i+1)
  
def quick_sort(arr, low, high):
    if low < high:
        pi = partition(arr, low, high)
        quick_sort(arr, low, pi-1)
        quick_sort(arr, pi+1, high)
    return arr
  
arr = [10, 7, 8, 9, 1, 5]
sorted_arr = quick_sort(arr, 0, len(arr)-1)
print("Sorted array is:", sorted_arr)

5. Dijkstra’s Algorithm: The Shortest Path Finder

One of the most famous algorithms for finding the shortest paths between nodes in a graph. It’s extensively used in routing and navigation technologies.

Learn more about Dijkstra’s Algorithm here.

import sys
 
class Graph():
    def __init__(self, vertices):
        self.V = vertices
        self.graph = [[0 for column in range(vertices)]
                      for row in range(vertices)]
  
    def min_distance(self, dist, spt_set):
        min = sys.maxsize
  
        for v in range(self.V):
            if dist[v] < min and spt_set[v] == False:
                min = dist[v]
                min_index = v
  
        return min_index
  
    def dijkstra(self, src):
        dist = [sys.maxsize] * self.V
        dist[src] = 0
        spt_set = [False] * self.V
  
        for cout in range(self.V):
            u = self.min_distance(dist, spt_set)
            spt_set[u] = True
  
            for v in range(self.V):
                if (self.graph[u][v] > 0 and
                   spt_set[v] == False and
                   dist[v] > dist[u] + self.graph[u][v]):
                        dist[v] = dist[u] + self.graph[u][v]
        return dist
  
g = Graph(9)
g.graph = [[0, 4, 0, 0, 0, 0, 0, 8, 0],
           [4, 0, 8, 0, 0, 0, 0, 11, 0],
           [0, 8, 0, 7, 0, 4, 0, 0, 2],
           [0, 0, 7, 0, 9, 14, 0, 0, 0],
           [0, 0, 0, 9, 0, 10, 0, 0, 0],
           [0, 0, 4, 14, 10, 0, 2, 0, 0],
           [0, 0, 0, 0, 0, 2, 0, 1, 6],
           [8, 11, 0, 0, 0, 0, 1, 0, 7],
           [0, 0, 2, 0, 0, 0, 6, 7, 0]]
  
shortest_paths = g.dijkstra(0)
print("Vertex \t\t Distance from Source")
for node in range(len(shortest_paths)):
    print(node, "\t\t", shortest_paths[node])

6. Floyd-Warshall Algorithm: All-Pairs Shortest Paths

Floyd-Warshall is another shortest path algorithm but it computes the shortest paths between all pairs of vertices in a weighted graph (with positive or negative edge weights).

V = 4
INF = 99999
  
def floyd_warshall(graph):
    dist = list(map(lambda i: list(map(lambda j: j, i)), graph))
    for k in range(V):
        for i in range(V):
            for j in range(V):
                dist[i][j] = min(dist[i][j], dist[i][k] + dist[k][j])
    return dist
  
graph = [[0, 5, INF, 10],
         [INF, 0, 3, INF],
         [INF, INF, 0, 1],
         [INF, INF, INF, 0]]
 
shortest_paths = floyd_warshall(graph)
print("Shortest distances between every pair of vertices")
for i in range(V):
    for j in range(V):
        if (shortest_paths[i][j] == INF):
            print("%7s" % ("INF"), end = " ")
        else:
            print("%7d" % (shortest_paths[i][j]), end = " ")
        if j == V-1:
            print()

7. Prim’s Algorithm: Minimum Spanning Tree

Prim’s Algorithm finds the Minimum Spanning Tree for a weighted undirected graph. The concept is simple: start from a node and grow the MST one edge at a time.

import sys
 
class Graph():
    def __init__(self, vertices):
        self.V = vertices
        self.graph = [[0 for column in range(vertices)]
                      for row in range(vertices)]
  
    def min_key(self, key, mst_set):
        min = sys.maxsize
  
        for v in range(self.V):
            if key[v] < min and mst_set[v] == False:
                min = key[v]
                min_index = v
  
        return min_index
  
    def prim_mst(self):
        key = [sys.maxsize] * self.V
        parent = [None] * self.V
        key[0] = 0
        mst_set = [False] * self.V
        parent[0] = -1
  
        for cout in range(self.V):
            u = self.min_key(key, mst_set)
            mst_set[u] = True
  
            for v in range(self.V):
                if self.graph[u][v] > 0 and mst_set[v] == False and key[v] > self.graph[u][v]:
                    key[v] = self.graph[u][v]
                    parent[v] = u
  
        return parent

8. Kruskal’s Algorithm: Another MST Algorithm

Much like Prim’s Algorithm, Kruskal’s algorithm also finds the Minimum Spanning Tree but it does so by sorting all edges and picking the smallest edge without forming a cycle.

class Graph:
    def __init__(self, vertices):
        self.V = vertices
        self.graph = []
  
    def add_edge(self, u, v, w):
        self.graph.append([u, v, w])
  
    def find(self, parent, i):
        if parent[i] == i:
            return i
        return self.find(parent, parent[i])
  
    def union(self, parent, rank, x, y):
        xroot = self.find(parent, x)
        yroot = self.find(parent, y)
  
        if rank[xroot] < rank[yroot]:
            parent[xroot] = yroot
        elif rank[xroot] > rank[yroot]:
            parent[yroot] = xroot
        else:
            parent[yroot] = xroot
            rank[xroot] += 1
  
    def kruskal_mst(self):
        result = []
        i = 0
        e = 0
        self.graph = sorted(self.graph, key=lambda item: item[2])
  
        parent = []
        rank = []
  
        for node in range(self.V):
            parent.append(node)
            rank.append(0)
  
        while e < self.V - 1:
  
            u, v, w = self.graph[i]
            i = i + 1
            x = self.find(parent, u)
            y = self.find(parent, v)
  
            if x != y:
                e = e + 1
                result.append([u, v, w])
                self.union(parent, rank, x, y)
  
        return result

9. Knapsack Problem: Choosing Wisely

The Knapsack Problem is a problem in combinatorial optimization. Given a set of items, each with a weight and a value, determine the number of each item to include in a collection such that the total weight is less than or equal to a given limit and the total value is as large as possible.

def knap_sack(W, wt, val, n):
    if n == 0 or W == 0:
        return 0
  
    if (wt[n-1] > W):
        return knap_sack(W, wt, val, n-1)
  
    else:
        return max(val[n-1] + knap_sack(W-wt[n-1], wt, val, n-1),
                   knap_sack(W, wt, val, n-1))
  
val = [60, 100, 120]
wt = [10, 20, 30]
W = 50
n = len(val)
print(knap_sack(W, wt, val, n))

10. Tower of Hanoi: The Classic Puzzle

The Tower of Hanoi is a mathematical game or puzzle. It consists of three rods and a number of disks of different sizes which can slide onto any rod.

def tower_of_hanoi(n, from_rod, to_rod, aux_rod):
    if n == 0:
        return
    tower_of_hanoi(n-1, from_rod, aux_rod, to_rod)
    print("Move disk", n, "from rod", from_rod, "to rod", to_rod)
    tower_of_hanoi(n-1, aux_rod, to_rod, from_rod)
  
n = 4
tower_of_hanoi(n, 'A', 'C', 'B')

Hope you enjoyed both the learning and the jokes! ?

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